Question

please someone solve this problem

Answer 1

sorry but it's not proper ...

Answer 2

d=b^2-4ac

a=k+1,b=2(k+1) and c=1,by applying this

d=o

=(-2(k+1))^2-4(k+1)(1)

=4(k+1)^2-4k-4

=4k^2+4+8k-4k-4

=4k^2+4k

=4k(k+1)=0

therefore k=o and k=-1

hope this answer is correct...............