Question

please someone solve this question

Answer 1

Solve it as given below :

Answer 2

HELLO DEAR,

9x²-15x+6=0


${(3x)}^{2} - 15x + 6 = 0 \\ = > {(3x)}^{2} - \frac{3 \times 5 \times 2\times x}{2} + {( \frac{5}{2} )}^{2} - {( \frac{5}{2} )}^{2} + 6 = 0 \\ = > ( {3x - \frac{5}{2} })^{2} - \frac{25}{4} + 6 = 0 \\ = > ( {3x - \frac{5}{2} })^{2} - \frac{25 + 24}{4} = 0 \\ = > ( {3x - \frac{5}{2} })^{2} = \frac{1}{4} \\ = > ( {3x - \frac{5}{2} })^{2} = { (\frac{1}{2} )}^{2} \\ = > ( {3x - \frac{5}{2} }) = + - \frac{1}{2} \\ = > ( {3x - \frac{5}{2} }) = - \frac{1}{2} \\ = > 3x = \frac{5 - 1}{2} \\ = > x = \frac{2}{ 3} \\ \\ = > ( {3x - \frac{5}{2} }) = \frac{1}{2} \\ = > 3x = \frac{5 + 1}{2} \\ = > x = \frac{6}{3 \times 2} \\ = > x = 1$
I HOPE ITS HELP YOU DEAR,
THANKS