Math, asked by Henry141, 1 year ago

Please someone solve this question

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Answered by hukam0685
3
let the fix charges be x Rupee's,
fair per km be y Rupee's
x + 10y = 105 \\ x + 15y = 155 \\
subtract both equations
 - 5y =  - 50 \\ y = 10
x + 10(10) = 105 \\ x + 100 = 105 \\ x = 5
s fix charges be 5 Rupee's.
per km fair be 10 Rupee's.
To travel for 25 km,he will pay
5 + 25(10) = 5 + 250 \\  = 255 \:  \: rupees




hukam0685: thanks
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