Math, asked by jyoti85826, 1 year ago

Please someone solve this question !!!

Prove that 8 root 5 is irrational !!​

Answers

Answered by akkshitaisa
3

Answer:

Step-by-step explanation:

Let 8 root 5 be a rational no.

Therefore 8 root 5 = p/q

P^2 = 8 root 5 q^2

8 root 5 is a factor of p^2

Therefore p = 8 root 5k

(8 root 5k)^2 = 8 root 5 q^2

Therefore 8^5 is also a factor of q

P and q are not co prime .

Therefore 8^5 cannot be rational

Hence proved that 8 root 5 is an irrational no.

Answered by deevena347
0

Answer:

Given: √5

We need to prove that √5 is irrational

Proof:

Let us assume that √5 is a rational number.

So it can be expressed in the form p/q where p,q are co-prime integers and q≠0

⇒ √5 = p/q

On squaring both the sides we get,

⇒5 = p²/q²

⇒5q² = p² —————–(i)

p²/5 = q²

So 5 divides p

p is a multiple of 5

⇒ p = 5m

⇒ p² = 25m² ————-(ii)

From equations (i) and (ii), we get,

5q² = 25m²

⇒ q² = 5m²

⇒ q² is a multiple of 5

⇒ q is a multiple of 5

Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√5 is an irrational number.

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