Question

please someone tell this questions answer full answer step by step​

Answer 1

L.H.S,

=sin - 2sin^3/2co^3-cos

=sin(1-2sin^2)/cos(2cos^2-1)

Use identity ,

sin^2+cos^2=1

=tan(sin^2+cos^2-2sin^2)/(2cos^2-sin^2-cos^2)

=tan(cos^2-sin^2)/(cos^2-sin^2)

=tan

R.H.S

Answer 2

Heres your answer...

hope it helps you:))