Math, asked by singhshivangi232233, 10 months ago

please sovle this question​

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Answered by Anonymous
0

ii)  \\  =  > x +  \frac{1}{x}  =  \sqrt{5}  \\  \\  =  >  {( x +  \frac{1}{x})}^{2}  =  { (\sqrt{5} )}^{2}  \\  \\  =  >  {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = 5 \\  \\  =  > {x}^{2}  +  \frac{1}{ {x}^{2} }   = 3

Answered by nssgourav2007
0

Answer:

Step-by-step explanation:

(ii) sqaureing on b/s

= x^{2} +2 +1/x^{2} = \sqrt{5}

=x^{2} +1/x^{2}  =5-2

=  therefore x^{2}  +1/x^{2} = 3

(i) x - 1/x

we need to subract - 4 on b/s because we need the answer in minus

= x^{2} +1/x^{2} + 2 -4 = 5-4

(x - 1/x)^2 = 1

if we send root that side \sqrt[2]{1}

= 1

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