please ssolve this by using Pythagoras theory
![{ac}^{2} = {13 }^{2} \\ {ab }^{2} = {15}^{2} find \: {bc}^{2} {ac}^{2} = {13 }^{2} \\ {ab }^{2} = {15}^{2} find \: {bc}^{2}](https://tex.z-dn.net/?f=+%7Bac%7D%5E%7B2%7D++%3D+%7B13+%7D%5E%7B2%7D++%5C%5C++%7Bab+%7D%5E%7B2%7D+%3D++%7B15%7D%5E%7B2%7D++find+%5C%3A++%7Bbc%7D%5E%7B2%7D+)
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Answered by
0
Given :
- AC² = 13².
- AB² = 15².
Find :
- Find BC².
Using Pythagorean theorem :
★ H² = √(A)² + (B)².
Calculations :
→ BC² = √(13)² - (15)²
→ BC = 225 - 169
→ BC = √394
→ BC = 56
Therefore, 56 is the required answer.
Answered by
1
Step-by-step explanation:
given that ;
ab ^2= 15^2 ; ac^2= 13^2
as it is right angle
ab^2- ac^2= bc^2
= 225- 169= bc^2
=bc^2= 56
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