Math, asked by Aadarshkumar8788440, 4 months ago

please step by step solution​

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Answered by parmanandmgrPrince
0

Answer:

We know that

area of triangle = 1/2*base*height

now

In triangle ABD,

it's height is 5.5cm and base is 10+8= 18 cm

now

Area of triangle = 1/2*b*h

=> 1/2*18*5.5

=> 49.5cm^2

Hence, area of triangle ABD = 49.5 cm^2

Step-by-step explanation:

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Answered by ab548
0

Answer: 74.25 cm.^{2}

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Step-by-step explanation:

In △ABD , using pythagorous theorem

AD = ( 10 + 8 ) cm. => 18 cm.

(BD)^{2} +(AB)^{2} =(AD)^{2} \\(AB)^{2} =(AD)^{2} -(BD)^{2} \\AB=\sqrt{(18)^{2}-(15)^{2}  }\\AB=\sqrt{3^{2}(36-25) } \\AB=3\sqrt{11} cm.

area ( △ ABD ) = \frac{1}{2} * base*height

=>   \frac{1}{2} *3\sqrt{11}*15

=>   \frac{1}{2} *9.9*15

=>   7.5*9.9

=>   74.25 cm.^{2}

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