Question

please steps explanation also please​

Answer 1

Answer:

Angle BEA = 70°

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$†Question:</p><p></p><p>In the given figuree, AB||CD, ∠EAB = 50° and ∠ECD = 60°, then find ∠AEB.</p><p></p><p>\bf{\dag}\:{\underline{\underline{\sf{Answer\::}}}}†Answer:</p><p></p><p>∠AEB = 70°</p><p></p><p>⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━</p><p>\bf{\dag}\:{\underline{\underline{\sf{Given\::}}}}†Given:</p><p></p><p>AB || CD</p><p></p><p>∠ECD = 60°</p><p></p><p>∠EAB = 50°</p><p></p><p>\bf{\dag}\:{\underline{\underline{\sf{To\:Find\::}}}}†ToFind:</p><p></p><p>∠AEB = ?</p><p></p><p>\bf{\dag}\:{\underline{\underline{\sf{Solution\::}}}}†Solution:</p><p>☯ Here, it is given that AB || CD. So, alternate interior angles will be equal. Therefore;</p><p></p><p>∠ECD = ∠EBA = 60°</p><p></p><p>By angle sum property we know that,</p><p>\quad\bigstar\:{\boxed{\sf{\pink{Sum_{(angles\:of\:triangle)} = 180^{\circ}}}}}★Sum(anglesoftriangle)=180∘</p><p>Therefore,</p><p>\begin{gathered}\\ :\implies\:\tt \angle{AEB} + \angle{EBA} + \angle{EAB} = 180\end{gathered}:⟹∠AEB+∠EBA+∠EAB=180</p><p>Putting all values,</p><p>\begin{gathered}\\ :\implies\:\tt \angle{AEB} + 60 + 50 = 180\end{gathered}:⟹∠AEB+60+50=180</p><p>\begin{gathered}\\ :\implies\:\tt \angle{AEB} + 110 = 180\end{gathered}:⟹∠AEB+110=180</p><p>\begin{gathered}\\ :\implies\:\tt \angle{AEB} = 180 - 110\end{gathered}:⟹∠AEB=180−110</p><p>\begin{gathered}\\ :\implies\:\large{\underline{\boxed{\tt{\red{\angle{AEB} = 70^{\circ}}}}}}\end{gathered}:⟹∠AEB=70∘</p><p>Related Question:</p><p></p><p>An angle of a quadrilateral measures five-third of a right angle and other three angles are equal. Find the measure of each equal angles of quadrilateral.</p><p></p><p>Answer:</p><p></p><p></p><p></p><p>Know more:</p><p></p><p>The lines which do not meet at any point i.e, the lines which do not cuts or touch each other at any point are called parallel lines.</p><p></p><p>Sum of angles of any quadrila</p><p></p><p>$