Question

please support me guys & answer this question.​

Answer 1

Answer : B

Step-by-step explanation:

As we know that 3 dice are thrown. We want prob. of sum on three faces at least 5 i.e, some may be 5 or more. We will find prob. of sum on three faces not 5 or less. i.e. sum on faces is 3 and 4 (1, 2 is not possible because of 3 dice).

No. of ways for sum on faces not 5 or more =4

[(1,1, 1), (1,2,1), (1, 1, 2). (2, 1, 1)]

Total out comes = 216.

Prob. of not 5 or more= 4/216

Prob. of sum on three faces at least 5 =1−4/216=212/216=53/54

Answer 2

Answer:

your answer is B ok byyyyyyyyyyy