Question

Please talk about it​

Answer 1

Instead of theta I've used A

$cot^2A- \frac{1}{sin^2A}$

$\frac{cos^2A}{sin^2A} - \frac{1}{sin^2A}$

$\frac{cos^2A-1}{sin^2A}$

$\frac{sin^2 A}{sin^2 A}$

= 1

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