Question

Please tap on it and solve !!​

Answer 1

|| ANSWER ||

HERE ( a = theta )

sin6a + cos6a = ( sin2a )3 + ( cos2 a ) 3

→ ( sin2 a + cos2 a ) ( sin4a - sin2a cos2a + cos2 a )

→ 1 ( sin4a - sin2a cos2a + cos4 a )

→ ( sin2 a ) 2 + ( cos2 a ) 2 - sin2 a cos2a

[as a2 +b2 = (a+b)2 - 2ab ]

→ ( sin2 a + cos2 a ) 2 - 2 sin2 a cos2 a - sin2 a cos 2 a

→ 1 - 3 sin2 a cos2 a

NOTE :-

• Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication, and division.
• To find the value of a , bring the variable to the left side and bring all the remaining values to the right side.
• Simplify the values to find the result.