Math, asked by khalkaraditya8, 10 months ago

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please solve the question,no spamming please​

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Answered by BrainlyPopularman
7

{ \bold{ \boxed{ \boxed{  \red{\bigstar \: ANSWER \: }}}}}

{ \bold{ \underline{Given} : - }} \\  \\ { \bold{ \orange{ \mathtt{ : \implies \: x + iy =  \sqrt{ \frac{a + ib}{c + id} }....(1) }}}} \\  \\ { \bold{ \orange{ \mathtt{  \: replace \:  \: i \:  \: with \:  \:  - i \: then - }}}} \\  \\ { \bold{ \orange{ \mathtt{ :  \implies \: x - iy =  \sqrt{ \frac{a - ib}{c - id} }....(2) }}}} \\  \\ { \bold{ \blue{ \mathtt{ multiply \:  \: equation \:  \: (1) \:  \: and \:  \: (2) -  }}}} \\  \\ { \bold{ \orange{ \mathtt{ :  \implies \: (x + iy)(x - iy) =  \sqrt{ \frac{a + ib}{c + id} \times  \frac{a - ib}{c - id}  }  }}}} \\  \\ { \bold{ \orange{ \mathtt{ :  \implies \:  {x}^{2} -  {(iy)}^{2}  =  \sqrt{ \frac{ {a}^{2}  -  {(ib)}^{2} }{ {c}^{2} -  {(id)}^{2}  } }  }}}} \\  \\ { \bold{ \orange{ \mathtt{ :  \implies \:  {x}^{2}  +  {y}^{2} =  \sqrt{ \frac{ {a}^{2} +  {b}^{2}  }{ {c}^{2}  +  {d}^{2} } }  }}}} \\  \\ { \bold{ \blue{ \mathtt{square \:  \: both \:  \: side - }}}} \\  \\ { \bold{ \orange{ \mathtt{ :  \implies \:{ \boxed{ {( {x}^{2} +  {y}^{2}  )}^{2}   =  \frac{ {a}^{2} +  {b}^{2}  }{ {c}^{2} +  {d}^{2}  } }}}}}} \\  \\ { \bold{ \red{ \huge \mathfrak{ \boxed{Hence  \:  \: proved} }}}}

Answered by shivisingh57
0

Answer:

Hello hello good morning ❣️❣️❣️❣️

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