Please tell 24th ...Its urgent please
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1/2+1/5+1/10=1/r
5+2+1/10=1/r
5/4= effective resistance
V=IR
6=5/4
total current= 4.8 ✓
I 1= v/r1
= 3 ✓
I 2= v/r2
6/5
= 1.2 ✓
I 3 = v/r3
= 0.6 ✓
5+2+1/10=1/r
5/4= effective resistance
V=IR
6=5/4
total current= 4.8 ✓
I 1= v/r1
= 3 ✓
I 2= v/r2
6/5
= 1.2 ✓
I 3 = v/r3
= 0.6 ✓
Answered by
0
Hello friend,
sorry for that in my whiteboard there is no more space that's why I am solving here.
your a) and question b) I have solved in my whiteboard......ok.
Now I am going to solve question number c).....ok.
let's go
C) The total effective resistance of the circuit.
We know that,
1/Rp = 1/R1 + 1/R2 + 1/R3
therefore,
1/Rp = 1/2+1/5+1/10
1/Rp = 5+2+1/10. .......(here we are taken taken the common multiple)
=. 8/10
= 0.8
therefore the total effective resistance of the circuit is 0.8 ohm.
I hope you like it......
#$#$$#$ Raju Singh ###
sorry for that in my whiteboard there is no more space that's why I am solving here.
your a) and question b) I have solved in my whiteboard......ok.
Now I am going to solve question number c).....ok.
let's go
C) The total effective resistance of the circuit.
We know that,
1/Rp = 1/R1 + 1/R2 + 1/R3
therefore,
1/Rp = 1/2+1/5+1/10
1/Rp = 5+2+1/10. .......(here we are taken taken the common multiple)
=. 8/10
= 0.8
therefore the total effective resistance of the circuit is 0.8 ohm.
I hope you like it......
#$#$$#$ Raju Singh ###
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Rajusingh45:
one small mistake is there ok.....just put 4.8 Ampear.
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