Math, asked by suryapradeep81p3ok3y, 1 year ago

Please tell..............

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Answers

Answered by kirtiprasanjenpchfhd
1
hope it helps u......
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Answered by harshitha006
1
i^33 =i^32 ×i
=(i^2)^16 ×i
=(-1)^16 ×i
=1×i
i^33 = i

i^67 =i^66 ×i
=(i^2)^32 ×i
(-1)^32 ×i
1×i
i^67 =i
now question becomes as
i + 1/i
take LCM
i^2 +1/i
1+(-1)/i
1-1/i
0/i
=0 is answer obtained

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