Physics, asked by jot5797, 1 year ago

please tell ...........✌

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Answered by helpingbuddy40

m=300kg
displacement=10m
work done in moving it along the inclined plane=force in the direction of displacement*displacement
=(300*9.8*cos60degree)*10=calculate kr lena^.^

helpingbuddy40: cos 30 degree ku liye ho?.it should be cos 60 degree 30 degree to inclined plane ka angle hai .Agr gravitational force ka component nikalna hai inclined plane ke direction me to 9.8*cos 60degree krenge.

helpingbuddy40: diagram bana lo achhe se samajh ayega

jot5797: mtlb aap ryt ho na

jot5797: mera bi aapka vala ans. aara h but book m aisa hi h

helpingbuddy40: haan bhai^_^

helpingbuddy40: book galat ho sakta hai

jot5797: ok... shukriaa

helpingbuddy40: teacher se puchh lena ho sake to

jot5797: ha.. kal

helpingbuddy40: ok

Answered by thibish

b)9800 is the answer as i think.

jot5797: tukka mt mar

thibish: what are you telling/

jot5797: plz don't guess give ryt ans.

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