Question

please tell answer ​

Answer 1

ANSWER :-

$3 {x}^{2} + 4(3x) + 5 = 3x \\ \\ 3 {x}^{2} + 12x - 3x + 5 = 0 \\ \\ 3 {x}^{2} + 9x + 5 = 0 \\ \\ x = - 9 + or - \frac{ \sqrt{ {9}^{2} - 4(3)(5) } }{2(3)} \\ \\ x = - 9+ or - \frac{ \sqrt{21} }{6} \\ \\ x = - 9 - \frac{ \sqrt{21} }{6} \\ or \: x = - 9 + \frac{ \sqrt{21} }{6}$

NOTE:-

• If ax^2 + bx + c represents a quadratic equation then the roots or solution is given by,
• $x = - b + or - \frac{ \sqrt{ {b}^{2} - 4ac } }{2a}$