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Step-by-step explanation:LET THE PRESENT A OF JACOB=x
THE PRESENT A OF JACOB'S SON=y
five year hence=x+5=3(y+5)-------(1)
five year ago = x-5=7(y-5)--------(2)
from eq 1
x+5=3(y+5)
x + 5=3y+15
x-3y=10--------3
from eq 2
x-5=7(y-5)
x-5=7y-35
x-7y= -30-----4
SOLVING EQ 3&4
x WILL come 40 year
y will come 10 year
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