Question

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Answer 1

Answer:

Given:- △ABC, right angled at C.

Two points D and E are on the sides AC and AB.

To prove:- AE2 +BD2 =AB2 +DE2

Construction:- Join the point D with B and E and point E with A.

Proof:-

Using pythagoras theorem,

Hypotenuse 2 =Perpendicular2 +Base2

In △ACE,

AE 2 =AC 2 +CE 2 .....(1)

In △BCD,

BD 2 =DC 2 +BC 2 .....(2)

In △ABC,

AB 2 =AC 2 +BC 2 .....(3)

In △DCE,

DE 2 =DC 2 +CE 2 .....(4)

Now,

AE 2 +BD 2 =AB 2 +DE 2

AC 2 +CE 2 +DC 2 +BC 2 =AC 2 +BC 2 +DC

2 +CE2

L.H.S. = R.H.S.

Hence proved.

Answer 2

Step-by-step explanation:

same answer in question