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Question :-
In the given figure, ABCD is a square of side 14 cm. Find the area of the shaded region.
Answer :-
In the given figure,
Diameter of 2 circles = Side of square ABCD
Diamter of 2 circles = 14 cm
Diameter of 1 circle = 7 cm
Radius of 1 circle = 7 / 2
Radius of 1 circle = 3.5 cm
Side of square PQRS = Radius of 2 circles
Side of square PQRS = 3.5 × 2 = 7 cm
Area of quadrant of one circle = πr² / 4
Area of quadrant of 4 circle = πr²
= 22 / 7 × ( 3.5 )²
= 22 / 2 × 3.5
= 11 × 3.5
= 38.5
Area of quadrant of 4 circle = 38.5 cm²
Area of square PQRS = 7 × 7
= 49
Area of square PQRS = 49 cm²
Area of shaded region = 49 - 38.5
= 10.5 cm²
Area of shaded region = 10.5 cm²
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