Math, asked by vermabrowny3, 1 year ago

please tell answer of question number 11 12 13

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Answered by AritraK
1
Dear friend,

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Q11.
P = Rs. 6500
R = ?
T = 3 yrs
A = Rs. 7930
SI = A - P = Rs. 1430

r = \frac{si \times 100}{pt} = \frac{1430 \times 100}{6500 \times 3} = \frac{22}{3}

Answer. Rate of interest is 22/3 p.a.

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Q12.
P = x
R = 7 % p.a.
T = 4 yrs
A = Rs. 5120
SI = A - P = 5120 - x

p = \frac{si \times 100}{rt}

x = \frac{5120 - x \times 100}{7 \times 4}

x = \frac{25(5120 - x)}{7}

7x = 128000 - 25x

32x = 12800

x = \frac{12800}{32} = 4000

Answer. The sum of money is Rs. 4000

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Q13.
P = Rs. 4500
R = 9 % p.a.
T = ?
A = Rs. 12600
SI = A - P = Rs. 8100

t = \frac{si \times 100}{pr} = \frac{8100 \times 100}{4500 \times 9} = 20

Answer. Time is 20 yrs.

Hope it helps !!!
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