Question

Please tell answer of this question

Answer 1

Mass of the girl $\sf{=40\ kg}$

Initial velocity of the girl $\sf{=5\ m\,s^{-1}}$

Mass of cart $\sf{=3\ kg}$

The cart was stationary so its initial velocity $\sf{=0\ m\,s^{-1}}$

After the girl jumping onto the cart, both the cart and girl move along with same velocity.

Let this velocity be $\sf{v.}$

Since there is no external unbalanced horizontal force acting on the system, the total linear momentum should be constant according to conservation of linear momentum.

Thus,

$\longrightarrow\sf{40\times5+3\times0=(40+3)v}$

$\longrightarrow\sf{200=43v}$

$\longrightarrow\sf{v=\dfrac{200}{43}}$

$\longrightarrow\sf{\underline{\underline{v=4.65\ m\,s^{-1}}}}$

Answer 2

Answer:

Hope it helps you........