Question

please tell answer urgently​

Answer 1

Answer:

1.

Explanation:

To prove :second equation of motion

Let

u=initial velocity

v=final velocity

a=acceleration

let the time be t and distance covered be s

Thus the area of the trapezium

=area of triangle ABD+ area of rectangle AODE

S= 1/2*AB*AD+(OD+OE)

S=1/2*DC*AD*(ut)

=1/2*at*t+ut

Thus, s=ut+1/2at^2

2. final velocity (v)= 0

initial velocity (u)=20m/s

distance =5cm= 0.05m

By the problem,

v^2-u^2=2as

0-400=0.1a

a=-400/0.1

=-4000m/s^2