Question

please tell answers​

Answer 1

sin3A = 3sinA - 4sin³A

cos 3A = 4cos³A - 3cosA

so, by simplification the result comes out to be

3-4sin²A - 4cos²A +3 =⟩ 6-4(sin²A+cos²A) =⟩ 6-4 =⟩ 2

hope it helped u a lot

please mark it as the brainliest answer

Answer 2

Answer:

Answer is option c) 2

Step-by-step explanation:

we know that,

Sin3A = 3SinA - 4Sin³A => SinA(3 - 4Sin²A)     --------------------(1)

Cos3A = 4Cos³A - 3CosA => Cos A(4Cos²A - 3)   ----------------(2)

Now lets substitute equations (1) And (2) in the question,

=> SinA(3 - 4Sin²A)/Sin A - Cos A(4Cos²A - 3)/CosA

here, SinA/SinA and CosA/CosA will get cancelled.

=> 3 - 4Sin²A - (4Cos²A - 3)

=> 3 - 4Sin²A - 4Cos²A + 3

=> 6 - 4Sin²A - 4Cos²A

=> 6 - 4( Sin²A + Cos²A )

Because Sin²A + Cos²A = 1

=> 6 - 4(1)

=> 6 - 4

=> 2.

therefore, 2 is the required answer.

REQUEST:

If you like the answer and explanation, please mark it as brainliest.