Please tell answers. Thank you
Answers
first question
Smita's age
let it b x
s'mother is 3 times of her age so it wud b
3x
Simta'age=x
S'mother's age=3x
After 10yr.
Smita's age x*10=10x
Her mothrs's age =3x*10=30x
smita's mother is twice Smita's age now
SO,
10x*2 =30x*2
20x=60x
x=3 Smira's present age is 3
And her mother's age= 3*10=30
2nd question
Total value of the three prizes = 1500 Let the value of the 1st prize = x
2nd prize = 5x/6
3rd prize = 4/5 × ( 5x/6) = 2x/3
x + 5x/6 + 2x/3 = 1500
[6x + 5x + 4x]/6 = 1500 [LCM =6]
15x/6 = 1500 15 x = 1500 × 6
15x = 9000 x = 9000/15
x = 600
Value of 1st prize = x = 600
Value of 2nd prize = 5x/6 = (5 x 600)/6 = 5x 100 500
3rd prize = 2x/3 =( 2 × 600)/3 = 2 × 200 = 400
Hence, the value of 1st prize, 2nd prize & 3rd prize is 600, 500 & ₹ 400
3rd question
Let x be the unit digit and y be tens digit. Then the original number be 10x + y.
Value of the number with reversed digits is 10y + x.
As per question, we have x + y : 12.... (1)
If the digits are reversed, the digits is greater than the original number by 18.
Therefore, 10y + x = 10x + y + 18 9x9y = -18.... (2)
Multiply equation (1) by 9, we get
9x + 9y = 108.... (3)
Add equations (2) and (3),
18x = 90
⇒x=5
Substitute this value in equation (1), we
get
5+ y = 12 ⇒ y = 7
Therefore, the original number is 10x + y = 10 x 5 + 7 = 57..
sorry dude I didn't got 4,5
hopes it's helpful