Question

please tell anyone fast because it's my test​

Answer 1

Answer:

sum is divided into two pages

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hope it helps you!!

Answer 2

Answer:

Step-by-step explanation:

              $\frac{5^{3x} }{5^{-4}} * \frac{25}{5^x} = \frac{5^{20}}{5^{12}}$

              $\frac{5^{3x} }{5^{-4}} * \frac{5^2}{5^x} = \frac{5^{20}}{5^{12}}$

              ${5^{3x} }*{5^{+4}} * {5^2}*{5^{-x} = {5^{20}}*{5^{-12}}$

              ${5^{3x+4+2-x} = {5^{20-12}}$          (because $a^x * a^y=a^{x+y}$)

          Since both sides the bases are same so we can equate the powers

             THEREFORE :

                      3x + 4 + 2 - x = 20 - 12

                       2x + 6 = 18

                       2x = 18 - 6

                       2x = 12

                        $x =\frac{12}{2}$

                        x = 6

                                         HOPE U UNDERSTOOD

                                                 THANK YOU