CBSE BOARD XII, asked by tenzin8888, 8 months ago

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A 20 cm long solenoid of cross-sectional area 2.5 cm^2 has 400 turns. Find (i) its self inductance (ii) the rate at which the current flowing through it should be changed so as to produce an induced emf of 100 micro volt.

Answers

Answered by javeriakhanam2808200
0

Answer:

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n=400turns,l=20cm,A=4cm

2

L=?

L=

100×100×20

1⋅25×10

−6

Hm

−1

×400×400×4×100

=4×10

−4

H

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