please tell D solution fast...I have to solve it urgently
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According to keplars law
t1²÷t2²≈r1³÷r2³
then
10power 11 ÷10power10whole cube =1000
t1²÷t2²=1000÷1
t1÷t2=√1000÷√1=31
6:1
t1²÷t2²≈r1³÷r2³
then
10power 11 ÷10power10whole cube =1000
t1²÷t2²=1000÷1
t1÷t2=√1000÷√1=31
6:1
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