Question

please tell don't spam otherwise I will report you hard​

Answer 1

Given

• Shape of field = equilateral triangle
• Perimeter of the field = 66m

To find

• Area of the triangle.

Solution

[First of all we need side of the triangular field to find area]

$\sf\pink{⟶}$ Since, all sides are equal of a equilateral triangle.

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Perimeter = 3a}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {66 = 3a}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {a = \dfrac{66}{3}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {a = 22}$

⠀

$\sf\pink{⟶}$ Now, using the formula area of a equilateral triangle we will find the area of the field.

$\large{\underline{\boxed{\tt{Area = \dfrac{\sqrt{3}}{4}a^2}}}}$

⠀

Now, solving further question

$\tt:\implies\: \: \: \: \: \: \: \: {Area = \dfrac{\sqrt{3}}{4}(22)^2}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = \dfrac{\sqrt{3}}{4} × 484}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = \sqrt{3} × 121}$

⠀

$\sf\blue{⟶}$ $\sqrt{3} = 1.73$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = 1.73 × 121}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = 209.33m^2}$

⠀

$\sf\purple{⟶}$ Hence, the area of the field is 209.33m².

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬