Question

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Answer 1

Answer:

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Answer 2

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If the dimensions of a triangular shaped wall are 15 , 6 and 11 m respectively . Find the area painted .

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Using heron's formula we get ,

s = $\frac{11\:+\:6\:+\:15}{2}$

s = $\frac{32}{2}$

s = 16

Now applying the value of s in the formula .

$\implies\:\sqrt{s\:(s\:-\:a)(s\:-\:b)(s\:-\:c)}$

$\implies\:\sqrt{16\:(16\:-\:11)(16\:-\:6)(16\:-\:15)}$

$\implies\:\sqrt{16\:\times\:5\:\times\:10\:\times\:1}$

$\implies\:\sqrt{800}$

$\implies\:20\sqrt{2}$