Question

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Answer 1

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Answer:

a = 5 and b = 2

Step-by-step explanation:

If ( x+1 ) is a factor of $2x^{3} + ax^{2} + 2bx$ + 1, then find the values of a and b given that 2 a –3 b = 4.

⇒ Given is the value of a and b.

given that ( x+1 ) is a factor of p ( x )

Therefore, -1 is a zero of given p ( x )

p ( x ) = $2 x 3 + ax^2 +2^bx + 1$

substituting the value of -1 in the given p ( x ) ,we get

 p( x ) = 2*( -1 ) 3 + a *( -1 ) 2 + 2*b*( -1 ) + 1

 = -2 + a -2b + 1

= -1 + a - 2b

or, a - 2 b = 1

also given that 2 a - 3 b = 4

so we got two equations;

a - 2 b = 7 ...(1)

2 a - 3 b = 4 ...(2)

( 1 )* ( 2 )* ( 4 ) -2 = 2 a - 4 b = .......(3)

( 2 ) *1 = 2 a - 3 b = 4 ............(4)

(4) -  (3) = [2 a - 2 a ] + [-3 b - (-4 b) = 4 - 2

-3 b + 4 b = 2

therefore b = 2

substituting the value of b in (3)

2 a - 4 b = 2

2 a - (4*2) = 2

2 a - 8 = 2

2 a = 2 + 8

2 = 10

a = $\frac{10} {2}$

Therefore a = 5

so we get the value of a and b

∴  a = 5 and b = 2

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$brainliest$ $plzz............$

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Miley............

Answer 2

Answer:

Step-by-step explanation:

Hope you got it