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Question no •8
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Given :-
● Consider a triangle ABC . Whose opposite angles are equal.
To Prove :-
● AB = AC
Construction:-
Draw a bisector of angle A such that it intersecting BC at D
Proof :-
Now, In ΔABC
In ΔBAD and ΔCAD
Angle B = Angle C. ( Given)
Angle BAD = Angle CAD
[By construction , D is the bisector of ΔA)
AD = AD ( Common)
By AAS congruence, ΔBAD and ΔCAD are congruent.
By CPCT
AB = AC
Hence, The side opposite to equal angles are equal in a triangle.
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