Question

please tell fast this question answers ​

Answer 1

Explanation:

1)three equation

i)v=u+at

ii)s=ut+1/2at²

iii)v²-u²=2as

2)i)v=u+at

25=0+a×5

25=a×5

a=5

s=ut+1/2at2

s=25×5+1/2×5×25

s=125+125/2

s=187.5m

ii)v=u+at

0=25+a×10

-25=a×10

a=-25/10

a=-2.5

iii)s=ut+1/2at²

s=25×10+1/2×2.5×100

s=250+125

s=375m

Answer 2

Answer:

3. here

initial velocity(v)=30mls

final velocitu(v)=0mls

time taken(t)=5 sec

here

we know that

s=v+u/2×t

=0+30/2×5

150/2

=75m

ii)= retardation=?

we know

v square=u square +2as

(0mls)square =30Square + 2a × 75m

0=900+150a

-900=159/a

-900/150=a

-6mls square=a

a=-6mls square

here the retardation is -6mls square

iii)

s=u+v/2 ×t

30+0/2×10

s= 150mso diatance is 150m