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3
(1) Given 30th term of the AP:10,7,4 is.
Answer: Option (C) : - 77
Explanation :
Given first term a = 10,
Last term n = 30.
common difference d = 7 - 10 = -3.
We know that sum of n terms an = a + (n - 1) * d
a30 = 10 + (30 - 1) * (-3)
= 10 + 29 * (-3)
= 10 + (-87)
= -77.
Therefore the 30th term of the AP is -77.
Answered by
2
Answer:
-77
Step-by-step explanation:
Given:-
a1 = 10
a2 = 7
a3 = 4
To find :- a30 or the 30th term
Solution:-
an = a + (n - 1)d
Here, an = a30
a = 10
n = 30
d = ?
So, a30 = a + (30 - 1)d
a30 = a +29d
Now find d
d = a2 - a1
d = 7 - 10
d = -3
Now , a30 = ?
a30 = a + 29d
a30 = 10 + 29(-3)
a30 = 10 - 87
a30 = -77
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