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Answers
Answer:
[9(³√64 + ³√125)³]^(0.25) = 9
Step-by-step explanation:
We have,
[9(³√64 + ³√125)³]^(0.25)
Now,
We need to know certain values and solving helpers to solve this problem,
We must know that,
³√64 = ³√(2³ × 2³)
= 2 × 2
= 4
So,
³√64 = 4 ------ 1
Similarly,
³√125 = ³√(5³)
= 5
So,
³√125 = 5 ------ 2
Also we should know that,
0.25 = (1/4) ------- 3
And we must know that,
(a^m) × (b^m) = (a × b)^m ------ 4
Also,
(a^m)^n = a^(m × n) ------ 5
Then we can solve the problem,
[9(³√64 + ³√125)³]^(0.25)
From eq.1, eq.2 and eq.3 we get,
= [9(4 + 5)³]^(1/4)
= [9¹ × (9)³]^(1/4)
Using the eq.4
= [9^(1 + 3)]^(1/4)
= [9⁴]^(1/4)
Using eq.5 we get,
= 9^(4 × (1/4))
= 9^(4/4)
= 9¹
= 9
Hence,
[9(³√64 + ³√125)³]^(0.25) = 9
Hope it helped you and believing you understood it...All the best