Math, asked by lonelypark09, 1 year ago

please tell - how do we do ques 4 and 5 ?

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Answers

Answered by ishanbajpai
1
g (x)=0
x=2
putting the values, we get the value of k
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lonelypark09: why did we put 2k=22?
lonelypark09: please tell...
lonelypark09: i got it. THANKS!!
ishanbajpai: you're welcome
Answered by bawejaesha02
1
(Q.4.)
I assume you know the Division algorithm, i.e. dividend=divisor*quotient+remainder.

if p(x) is completely divisible by x-2, the remainder will be 0.
So, divide (3x²-kx+10) by (x-2) in such a way that the remainder is zero. From that you will find that the value of k is 1.

 (Q.5.)

You probably know that a²-b²=(a+b)(a-b)

In this question, let a = x²+y²-z²  and b = x²-y²+z².

So, (x²+y²-z²)²  - (x²-y²+z²)² = (x²+y²-z²+x²-y²+z²)(x²+y²-z²-x²+y²-z²)
=2x²×(2y²-2z²)
=4x²y²-4x²z²

lonelypark09: can you please tell ques 4 in a bit more detail?
lonelypark09: i am having a little bit doubt.
lonelypark09: i got it...Thanks!
bawejaesha02: Sure
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