Question

please tell how to do​

Answer 1

Solution

2(x -2) + 3(4x -1) = 0

Firstly solve these brackets

$\implies$2x - 4 + 12x - 3 = 0

$\implies$14x -7 = 0

$\implies$14x = 7

$\implies$x = $\dfrac{7}{14}$

$\implies$x = $\dfrac{1}{2}$

Hope it helps

Answer 2

Step-by-step explanation:

Given : A linear equation $2(x-2)+3(4x-1)=0$

To find : the vale of x and check the answer.

• Calculation for x,

We have a linear equation and to solve it first of all we have to do multiplication for opening the brackets.

⇒ $2(x-2)+3(4x-1)=0$         --(1)

⇒ $2*x+2*(-2)+3*(4x)+3*(-1)=0$

⇒ $2x-4+12x-3=0$

add similar terms and get the value of x,

⇒ $14x-7=0$

⇒ $14x=7$

⇒ $x=\frac{7}{14}$

⇒ $x=\frac{1}{2}$

we get he value of x is $\frac{1}{2}$.

• Checking the answer,

To check the answer put the value of x in equation (1),

⇒ $2(x-2)+3(4x-1)=0$

⇒ $x=\frac{1}{2}$

If by putting x the equation will zero then it means our value of x is correct.

⇒ $2(\frac{1}{2} -2)+3(4*\frac{1}{2}-1)$

$=2(\frac{1-4}{2})+3(2-1)$

$=2(\frac{-3}{2} )+3*1$

$=-3+3$

$=0$

This means our value of x is correct this is verified.