please tell how to take out pythagorean triplet by using general form
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The general formula for Pythagorean triples can be shown as, a2 + b2 = c2, where a, b, and c are the positive integers that satisfy this equation, where 'c' is the "hypotenuse" or the longest side of the triangle and a and b are the other two legs of the right-angled triangle.
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The simple formula to find the Pythagorean triplet is a^2+b^2=c^2
Where, a and b are small numbers and the sum of their squares is equal to the third no.s (greatest no) square.
For ex. 6^2+8^2=10^2
:. 36+64=100
100=100
Hope you got this
Where, a and b are small numbers and the sum of their squares is equal to the third no.s (greatest no) square.
For ex. 6^2+8^2=10^2
:. 36+64=100
100=100
Hope you got this
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