Question

please tell it is so important

you have to factorise it

Answer 1

4a²-9b²-2a-3b
=>[(2a)²-(3b)²]-(2a+3b)

using formula a²-b² = (a+b)(a-b)
=> (2a-3b)(2a+3b)-(2a+3b).................(i)


from equation i when we take (2a+3b) common then we get this
=> (2a+3b)(2a-3b-1)


hope this helps

Answer 2

ANSWER
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4a^2 - 9b^2 - 2a - 3b

=> [ (2a)^2 - (3b)^2 ] - 2a - 3b

Using formula, a^2 - b^2 = (a+b) (a-b)

=> (2a+3b) (2a-3b) - 2a - 3b

Take negative common

=> (2a+3b) (2a-3b) - (2a + 3b)

Take 2a + 3b common

=> (2a + 3b) (2a - 3b - 1)

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ANSWER = (2a + 3b) (2a - 3b - 1)

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HOPE IT HELPS :):):):)