Question

please tell..... it's very important I have to do it in fair copy . plzzz tell​

Answer 1

Answer:

15cm draw perpendicular from centre to chord and apply pythagoras theorem

Answer 2

$\bf \underline{GIVEN}$

Radius of circle = 17cm

Length of chord = 16cm

$\bf \underline{TO \: FIND}$

The distance of chord from the centre.

$\bf \underline{SOLUTION}$

Let the chord be PQ and center be O.

And the perpendicular from center to the chord be R.

∵ We know that, perpendicular bisects the chord into two equal line segments.

ㅤ✏ PR = QR = PQ/2 = 16/2 = 8cm.

Given, Radius = OQ = 17cm

Now,

We've to find OR or distance between center and chord.

➸ By Pythagoras Theorem,

$\sf\implies( oq) {}^{2} = (OR) {}^{2} + (QR) {}^{2}$

$\sf \implies \: (17) {}^{2} = OR {}^{2} + (8) {}^{2}$

$\sf \implies \: OR {}^{2} = (17) {}^{2} - (8) {}^{2}$

$\sf \implies \: OR = \sqrt{289 - 64}$

$\large \implies \boxed {\boxed {\tt \blue {OR = 15cm }}}$

$\tt \therefore \underline{\red{The \: distance\: between \:chord \:and\: center\: is \:15cm }}.$