Science, asked by falaksaifi833, 8 months ago

Please tell me 24g Hiliyam mai parmaanduo ki sankhya ka priklan kijiye (He=4u)

Answers

Answered by Anonymous

1

Answer:

In 4g = Na atoms

Then in 24g= 6 Na atoms 9f He is present.

Reference: Na = Avogardos number = 6.022× 10^(-23)

Explanation:

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