Question

please tell me accurate answer of this class 9

Answer 1

here is your answer
4 initial velocity u=0
Acceleration a=4ms-2
time t =10s
distance covered s=?
we know that S =ut + 1/2 at 2
S = 0x 10 +1/2 x 4 x (10)2 = 0+ 200=200m
therefore distance covered = 200m
5
initial velocity u = 5ms-1
final velocity v = 0
acceleration in the downward direction = 10ms-2
therefore acceleration in the upward direction a = -10 ms-2
height attained by stone S =?
time taken to attain height T = ?
using the relation v = u + at
0 = 5 + (-10)t
t = 5/10=0.5 s
or
using the relation v2 - u2 = 2aS
we have
S = v2 - u2/2a
= (0)2 - (5)2/20x(-10)
= 1.25m
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