Question

please tell me all the answers faster because I have a exam tomorrow​

Answer 1

Answer:

abe kud padhi kar le exam hai tho

Answer 2

Step-by-step explanation:

1)

$5(1 - x) + 3(1 + x) = 8(1 - 2x)$

$5 - 5x + 3 + 3x = 8 - 16x$

$8 - 2x = 8 - 16x$

$14x = 0$

$x = 0$

2)

$2y - 3 - (6y - 10) \div 4 = 4y + 3 \div 4$

$2y - 6y - 3 + 10 = 4y + 3$

$- 8y = 3 - 7$

$y = + 1 \div 2$

3)

${x}^{2} + 3x + 2x + 6( {x}^{2} + 4x - x - 4) = 0$

${x}^{2} + 5x + 6 - {x}^{2} - 3x + 4 = 0$

$2x + 10 = 0$

$x = - 5$

4) sorry i dont know this question

sorry i cant help u more than this because i know these questions only

hope it helps u

❤ all the best for your exam