Math, asked by apooravdhadda, 4 months ago

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Answered by sakshi2477
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Answer:

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Step-by-step explanation:

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Answered by krish1973
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Step-by-step explanation:

Let the work done by man and woman per day be x and y respectively.

When the work is completed in 4 days

Since 5 men and 2 women complete the work in 4 days

therefore work done by 5 men and 2 women in 1 day = 1/4

∴5x+2y= 1/4⟶eq 1

When the work is completed in 3 days

Since 6 men and 3 women complete the work in 3 days

therefore work done by 6 men and 3 women in 1 day = 1/3

∴6x+3y= 1/3⟶eq 2

Multiplying by 3 in eq 1, we get

⇒15x+6y= 3/4⟶eq 3

Multiplying by 2 in eq

n

2, we get

⇒12x+6y= 2/3 ⟶eq 4

On subtracting eq 4 from eq 3, we get⇒15x+6y−12x−6y= 3/4 -2/3

⇒3x= 1/12

⇒x= 1/36

On substituting the value of x in eq 2, we get

⇒6× 1/36 +3y=1/3

⇒3y= 1/3 - 1/6

⇒y= 1/18

Thus,

work done by 1 man in 1 day = 1/36days

∴ Time taken by 1 man alone to finish the work =36 days

work done by 1 woman in 1 day = 1/18 days

∴ Time taken by 1 woman alone to finish the work =18 days.

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