please tell me answer
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BOC= 35-10
BOC= 25°
fshsgsg:
answer is 25
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Hope it helps u
angle BOC + angle COA = angle AOB
.°.(x-10)°+(2x-5)° =90°
.°. x-10°+2x-5° =90°
.°. x+2x-10°-5° =90°
3x-15°=90°
3x=90°+15°
3x=105°
.°.x=105/3
x= 35°
.°. angle BOC = (x-10°)
= 35°-10°
= 25°
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