Math, asked by rahamkajal, 11 months ago

please tell me answer​

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Answered by Anonymous
2

Answer:

3y-5 = 70°

-4x = 60°

-7x+5 = 110°

4y + 20 = 120°

Step-by-step explanation:

Opposite angles of a cyclic quadrilateral are supplementary (add up to 180°).

So...

4y + 20° - 4x = 180°     ... (1)

3y - 5° - 7x + 5° = 180°   ... (2)

From (1):

4y - 4x = 160°  =>  y - x = 40°  =>  y = x + 40°    ... (3)

Substituting this into (2) gives:

3(x+40°) - 5° - 7x + 5° = 180°

=> 3x + 120° - 7x = 180°

=> -4x = 60°

=> x = -15°

From (3):

y = -15° + 40° = 25°.

Therefore the angles are:

3y-5 = 70°

-4x = 60°

-7x+5 = 110°

4y + 20 = 120°

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