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Answer:
3y-5 = 70°
-4x = 60°
-7x+5 = 110°
4y + 20 = 120°
Step-by-step explanation:
Opposite angles of a cyclic quadrilateral are supplementary (add up to 180°).
So...
4y + 20° - 4x = 180° ... (1)
3y - 5° - 7x + 5° = 180° ... (2)
From (1):
4y - 4x = 160° => y - x = 40° => y = x + 40° ... (3)
Substituting this into (2) gives:
3(x+40°) - 5° - 7x + 5° = 180°
=> 3x + 120° - 7x = 180°
=> -4x = 60°
=> x = -15°
From (3):
y = -15° + 40° = 25°.
Therefore the angles are:
3y-5 = 70°
-4x = 60°
-7x+5 = 110°
4y + 20 = 120°
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