Question

please tell me answer fast......​

Answer 1

Answer:

$\text{at } t=1\text{s} \\ \text{position of particle } \vec r_1 = 3\hat \imath + 4(1)^2\hat \jmath -(1)^3\hat k \\ \vec r_1= 3\hat \imath+4\hat \jmath -1\hat k \\ \text{position of particle } \vec r_2 = 3\hat \imath + 4(3)^2\hat \jmath -(3)^3\hat k \\ \vec r_2= 3\hat \imath + 36\hat \jmath -27\hat k \\ \text{displacement vector } \vec d=\vec r_2-\vec r_1 \\ \vec d= 32\hat \jmath-26\hat k$