Question

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Answer 1

Answer:

Question:

How much momentum will a bell of mass 10 kg transfer to the floor if it falls from height of 80 cm ? Take its downward acceleration to be 10 m s-².

Given:

Given:Mass of the bell = 10 kg

Height from the floor = 80 cm or 0.8 m

Height from the floor = 80 cm or 0.8 mAcceleration to downward = 10 m s-²

To find:

The momentum of the bell

Concept:

First find the final velocity then find the momentum .

Taken:

Initial velocity (v)= 0

Final velocity = v

(To find the momentum first find the final velocity of the bell)

According to the third rd equation of the motion

$\bold\green{v²=u²+2ah}$

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

h = Height

$\bold\green{s=m×v}$

Where,

s = Momentum

m = Mass

v = Final velocity

Solution:

Final velocity:

$\bold\green{Taken,v²=u²+2ah}$

$\bold{v²=(0)²+2×10×0.8}$

$\bold{ v²-(0)²=20×0.8}$

$\bold{ v = \sqrt{20 \times 0.8} }$

$\bold{ v = \sqrt{16} }$

$\bold{v = 4 \: m .s}$

____________________________

Momentum:

$\bold\green{Taken,s=m×v}$

$\bold{s=10kg×4m/s}$

$\bold{s=40kg.m/s-¹}$