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Q-4 = 140÷[4+{10×(5-4)}]
= 140÷[4+{10×(1)}]
= 140÷[4+{10}]
= 140÷[14]
= 10
Step-by-step explanation:
Q-5. The prime factors of 101 = 1 and 101,573 = 1,3,191 but the common factor is 1. Therefore, the HCF of 101, 573 and 1079 = 1.
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