Question

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Answer 1

Answer:

Question.4(A) AB=CD(4.5cm)

BC=BC(Common)

AC=BD(4cm)

Therefore, ∆ABC is congruent to ∆BCD(S.S.S.)

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Answer 2

In triangle BDC and triangle ACB

cb = cb ( common)

bd = ac ( both 4 cm )

ab = cd ( both 4.5 cm )

hence triangle BDC congruent triangle ACD by sss rule